 Posted: Tue 4:55, 05 Apr 2011 Post subject: Momentum, conservation of momentum and the referen |
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| Momentum, conservation of momentum and the reference
Of reference, there are still problem-solving using the momentum theorem can be won for the introduction of a particle on the fictional rejection in the instantaneous inertial force, the size of the m. . The direction of a, t 一号 but enjoy the power of rhyme to the punch stroke fEE set, you can refer to the formula (2), as J. f * d: t, and weeks' ● j = a m-ao) dt Therefore, the size of the impulse inertia force is equal to (mu-m., direction and beam motion sickness mu mu with the first motion vector difference mildew in the opposite direction. the formula (1O) on behalf of the eight formula (* 9) was + apricot = a m,tory burch outlet, the formula (-I-1) showed that: in (± a t. time, non-inertial reference frame relative to the increment of particle momentum equal to the period when the servers l the bombing of Si-thousand Chang points Bai Xi external http impulse and inertial force of the impulse vector halo and He of the non-inertial reference sin rice in the particle l momentum (the switch to algae Shai dance _ Di One swallow ● a towel .; blast 0l ') ¨ ¨ a m-u one. mmm ((eleven = l1, ● bamboo mat. The function of the change in the amount equal to the open interval (a, b) the derivative of a point and the change in the independent variable of the product. This product Xun value is the change in function, the exact value. ② If the formula in that a = x, b = x + Ax, then b-a = Ax, then f (x + Ax a (f) x (= f ({) Ax (x <§ <x + Ax), ie Ay = f (§) Ax ③ this formula from the theory is the calculation of the function into the function increment f (x) in the open interval (8, b) derivative of a point within the f, (1) and △ x of the product. So, on some issues, when the independent variable increment Ax had limited value, and function of the increment △ y require accurate expression, Lagrange mean value theorem to show its superiority, reflecting the great practical value. And in the theorem, and does not require the independent variable increment Ax = b-a tends to zero or comparatively small, and requires only a limited incremental, so that the increment Ay function can accurately be expressed as Ay = f (1) Ax. This result is different with the differential, but can be approximated by differential function dy Y = f (x) incremental, that is Aydy = f (x) △ x, in this style house, requiring lAx1 comparatively small, and only if △ x 10 when approximated by dy Ay trend of the error before to zero. so Lagrange's theorem is also known as finite increment theorem. In addition, l can also be used for another form of that from a <l <b we know 0 <l-a <b-a, <aa a <1, so 0 = Xi India l = a +0 (b-a) (0 <e <1).. Therefore, the formula is also often written as Lagrange's theorem f (b) a f (a) = f (a +0 (b-a)) (b-B) ④ where 0 satisfy 0 <e <1 in a number of 6.. in the Lagrange mean value theorem, saying only that l must exist in the open interval (a, b), except where the location of the point l, the exact point value is the number of l, and l find the specific methods, theorems and there are not any instructions. Even so, it does not prevent us from using the pull Japan Grand mean value theorem. because in theory the Lagrange mean value theorem has been given Y = (x) and its derivative Y (x) stored on a given interval nature of the links of some , and Lagrange mean value theorem, offenders are usually able to function under the guidance Y = f (x) the characteristics can be introduced or argument on the function Y = f (x) in the given interval of some important properties. so pull Grand project in the Differential Mean Value Theorem is a very important theorem in mathematics is the most important and one of the most widely used theorem. (Continued from page 32) Theorem. Equation (11) and formulas ( 2) are similar, we can see into the inertial force 【head impulse, the non-inertial reference frame the momentum theorem and the theorem of momentum in the inertial reference system, has the same form, for which, in non-inertial reference frame of particle dynamics the law, you can still use the theorem of momentum in non-inertial reference frame, particle group theorem of momentum in the form of rt-rt one hundred and eleven IEFdt + lf.dt = Σmvi a Σmfvf. (12) Jt. t. - one from the formula (i2) know that when ΣFj = 0, that is not subject to external forces the particle group, or combined force is zero, the particle inertia group suffered can not be zero, so the system momentum is not conserved. - In short, in non-inertial reference frame, the introduction of inertia force and inertia force, after the impulse of the particle (or particle group), you can still use the momentum theorem to solve problems, but the momentum of particle group is not conserved. _-' i XI .- Hong Sheng. Og a 13 one. ● ∥ |
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